Determine Duration between Two Dates

All
I have a table of members and I would like to determine how long each member
has been a member based upon the current date. I would like the result
retuned in the Number of Years, Months and Days ie. 5y 6m 26d. Any
assistance would be appreciated.
CREATE TABLE member
(
MemberID INT,
DateJoined SMALLDATETIME
)
INSERT INTO member SELECT 1, '1999-01-11 00:00:00'
INSERT INTO member SELECT 2, '2004-12-26 00:00:00'
INSERT INTO member SELECT 3, '2005-01-01 00:00:00'
Desired Result:
1 1999-01-11 2005-10-13 6y 9m 2d
2 2004-12-26 2005-10-13 0y 10m 18d
3 2005-01-01 2005-10-13 0y 10m 12d
ThanksHi David,
There must be a simpler way than this, but what the heck...
SELECT id, dt, y, m,
diff_d - CASE WHEN dt_ym + diff_d > today THEN 1 ELSE 0 END AS d
FROM
(
SELECT *, DATEDIFF(day, dt_ym, today) AS diff_d
FROM
(
SELECT id, dt, today, y, m,
DATEADD(month, m, dt_y) AS dt_ym
FROM
(
SELECT id, dt, today, y, dt_y,
m_diff - CASE WHEN DATEADD(month, m_diff, dt_y) > today
THEN 1 ELSE 0 END AS m
FROM
(
SELECT *, DATEDIFF(month, dt_y, today) AS m_diff
FROM
(
SELECT *, DATEADD(year, y, dt) AS dt_y
FROM
(
SELECT id, dt, today,
y_diff - CASE WHEN DATEADD(year, y_diff, dt) > today
THEN 1 ELSE 0 END AS y
FROM
(
SELECT *, DATEDIFF(year, dt, today) AS y_diff
FROM
(
SELECT MemberID AS id, DateJoined AS dt,
CAST(CONVERT(VARCHAR(8), GETDATE(), 112) AS DATETIME) AS today
FROM member
) AS D1
) AS D2
) AS D3
) AS D4
) AS D5
) AS D6
) AS D7
) AS D8;
BG, SQL Server MVP
www.SolidQualityLearning.com
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"David" <David@.discussions.microsoft.com> wrote in message
news:44CF768B-1213-453F-8A62-024857AF5089@.microsoft.com...
> All
> I have a table of members and I would like to determine how long each
> member
> has been a member based upon the current date. I would like the result
> retuned in the Number of Years, Months and Days ie. 5y 6m 26d. Any
> assistance would be appreciated.
> CREATE TABLE member
> (
> MemberID INT,
> DateJoined SMALLDATETIME
> )
> INSERT INTO member SELECT 1, '1999-01-11 00:00:00'
> INSERT INTO member SELECT 2, '2004-12-26 00:00:00'
> INSERT INTO member SELECT 3, '2005-01-01 00:00:00'
>
> Desired Result:
> 1 1999-01-11 2005-10-13 6y 9m 2d
> 2 2004-12-26 2005-10-13 0y 10m 18d
> 3 2005-01-01 2005-10-13 0y 10m 12d
>
> Thanks|||Hi David
Probably you can check the link.
http://chanduas.blogspot.com/2005/0...lating-age.html
This is not the exact solution but can give u an idea
please let me know if u have any questions
best Regards,
Chandra
http://chanduas.blogspot.com/
http://www.SQLResource.com/
---
"David" wrote:

> All
> I have a table of members and I would like to determine how long each memb
er
> has been a member based upon the current date. I would like the result
> retuned in the Number of Years, Months and Days ie. 5y 6m 26d. Any
> assistance would be appreciated.
> CREATE TABLE member
> (
> MemberID INT,
> DateJoined SMALLDATETIME
> )
> INSERT INTO member SELECT 1, '1999-01-11 00:00:00'
> INSERT INTO member SELECT 2, '2004-12-26 00:00:00'
> INSERT INTO member SELECT 3, '2005-01-01 00:00:00'
>
> Desired Result:
> 1 1999-01-11 2005-10-13 6y 9m 2d
> 2 2004-12-26 2005-10-13 0y 10m 18d
> 3 2005-01-01 2005-10-13 0y 10m 12d
>
> Thanks